get_earth

sunpy.coordinates.ephemeris.get_earth(time='now', *, include_velocity=False)[source]

Return a SkyCoord for the location of the Earth at a specified time in the HeliographicStonyhurst frame. The longitude will be zero by definition.

Parameters
Returns

out (SkyCoord) – Location of the Earth in the HeliographicStonyhurst frame

Notes

The Earth’s velocity in the output coordinate will invariably be negligible in the longitude direction because the HeliographicStonyhurst frame rotates in time such that the plane of zero longitude (the XZ-plane) tracks Earth.

Examples

>>> from sunpy.coordinates.ephemeris import get_earth
>>> get_earth('2001-02-03 04:05:06')
<SkyCoord (HeliographicStonyhurst: obstime=2001-02-03T04:05:06.000, rsun=695700.0 km): (lon, lat, radius) in (deg, deg, AU)
    (0., -6.18656962, 0.98567647)>
>>> get_earth('2001-02-03 04:05:06', include_velocity=True)
<SkyCoord (HeliographicStonyhurst: obstime=2001-02-03T04:05:06.000, rsun=695700.0 km): (lon, lat, radius) in (deg, deg, AU)
    (0., -6.18656962, 0.98567647)
 (d_lon, d_lat, d_radius) in (arcsec / s, arcsec / s, km / s)
    (6.42643739e-11, -0.00279484, 0.24968506)>
>>> get_earth('2001-02-03 04:05:06', include_velocity=True).transform_to('heliocentricinertial')
<SkyCoord (HeliocentricInertial: obstime=2001-02-03T04:05:06.000): (lon, lat, distance) in (deg, deg, AU)
    (58.41594489, -6.18656962, 0.98567647)
 (d_lon, d_lat, d_distance) in (arcsec / s, arcsec / s, km / s)
    (0.0424104, -0.00279484, 0.2496851)>